Lexicon of Arguments

 

I 200
Bertrand's Paradox/Barrow: we want to calculate with which probability a randomly drawn secant of a circle is longer than the side of the equilateral triangle inscribed in the circle. The equidistant events are 1/2, 1/4, or 1/3, depending on the choice of the starting point (which entails consequences).
Therefore the probability cannot be estimated completely mechanically. A subjective assessment of the "global" nature of the problem is necessary to make the meaning of the solution clear.
Bertrand's paradox/probability/Barrow: Bertrand's paradox shows that probability cannot be mechanically estimated, it must be delimited by a first choice.
>Probability, cf. >Preferences, cf. >Arrow's theorem.